数码管动态显示C语言程序
发布网友
发布时间：2022-04-22 00:49
共3个回答
热心网友
时间：2022-07-08 03:28
记得给分哦！
我这个程序是在ICCVC FOR AVR 那个编译器里编译成功的
//ICC-AVR application builder : 2010-3-15 11:14:29
// Target : M8
// Crystal: 4.0000Mhz
#include <iom8v.h>
#include <macros.h>
unsigned char const seg_table[10]={0xC0,0xF9,0xA4,0xB0,0x99,0x92,0x82,0xF8,0x80,0x90};
void port_init(void)
{
PORTB = 0xFF;
DDRB = 0xFF;
PORTC = 0x00; //m103 output only
DDRC = 0x00;
PORTD = 0x00;
DDRD = 0x00;
}
//call this routine to initialize all peripherals
void init_devices(void)
{
//stop errant interrupts until set up
CLI(); //disable all interrupts
port_init();
MCUCR = 0x00;
GICR = 0x00;
TIMSK = 0x00; //timer interrupt sources
SEI(); //re-enable interrupts
//all peripherals are now initialized
}
/* 微秒级延时程序 */
void delay_us(int time)
{
do
{
time--;
} while (time>1);
}
/* 毫秒级延时程序 */
void delay_ms(unsigned int time)
{
while(time!=0)
{
delay_us(1000);
time--;
}
}
void main()
{
unsigned char i;
init_devices();
while (1)
{
for (i=0;i<10;i++)
{
PORTB=seg_table[i];
delay_ms(100);
}
}
}
热心网友
时间：2022-07-08 03:29
void CMyClockDlg::DrawSingleNumber(int nNum, int nLeft)
{
switch (nNum)
{
case 0:
DrawSection1(nLeft);
DrawSection2(nLeft);
DrawSection3(nLeft);
DrawSection4(nLeft);
DrawSection5(nLeft);
DrawSection6(nLeft);
break;
case 1:
DrawSection2(nLeft);
DrawSection3(nLeft);
break;
case 2:
DrawSection1(nLeft);
DrawSection2(nLeft);
DrawSection4(nLeft);
DrawSection5(nLeft);
DrawSection7(nLeft);
break;
case 3:
DrawSection1(nLeft);
DrawSection2(nLeft);
DrawSection3(nLeft);
DrawSection4(nLeft);
DrawSection7(nLeft);
break;
case 4:
DrawSection2(nLeft);
DrawSection3(nLeft);
DrawSection6(nLeft);
DrawSection7(nLeft);
break;
case 5:
DrawSection1(nLeft);
DrawSection3(nLeft);
DrawSection4(nLeft);
DrawSection6(nLeft);
DrawSection7(nLeft);
break;
case 6:
DrawSection1(nLeft);
DrawSection3(nLeft);
DrawSection4(nLeft);
DrawSection5(nLeft);
DrawSection6(nLeft);
DrawSection7(nLeft);
break;
case 7:
DrawSection1(nLeft);
DrawSection2(nLeft);
DrawSection3(nLeft);
break;
case 8:
DrawSection1(nLeft);
DrawSection2(nLeft);
DrawSection3(nLeft);
DrawSection4(nLeft);
DrawSection5(nLeft);
DrawSection6(nLeft);
DrawSection7(nLeft);
break;
case 9:
DrawSection1(nLeft);
DrawSection3(nLeft);
DrawSection4(nLeft);
DrawSection2(nLeft);
DrawSection6(nLeft);
DrawSection7(nLeft);
break;
default;
}
}
}
void CMyClockDlg::DrawSection1(int nLeft)
{
if (m_memDC.m_hDC!=NULL)
{
CPoint point[4];
point[0].x=nLeft+(int)(0.1*m_nWidth);
point[0].y=m_nYmargin;
point[1].x=nLeft+(int)(0.9*m_nWidth);
point[1].y=m_nYmargin;
point[2].x=nLeft+(int)(0.7*m_nWidth);
point[2].y=(int)(0.2*m_nWidth)+m_nYmargin;
point[3].x=nLeft+(int)(0.3*m_nWidth);
point[3].y=(int)(0.2*m_nWidth)+m_nYmargin;
CBrush br(m_crText);
CRgn rgn;
rgn.CreatePolygonRgn(point,4,ALTERNATE);
m_memDC.FillRgn(&rgn,&br);
br.DeleteObject();
rgn.DeleteObject();
m_memDC.MoveTo(point[0]);
m_memDC.LineTo(point[1]);
m_memDC.MoveTo(point[1]);
m_memDC.LineTo(point[2]);
m_memDC.MoveTo(point[2]);
m_memDC.LineTo(point[3]);
m_memDC.MoveTo(point[3]);
m_memDC.LineTo(point[0]);
}
}
void CMyClockDlg::Draw2Dot(int nLeft)
{
if (m_memDC.m_hDC!=NULL)
{
CBrush br(m_crText);
CRect rect;
rect.SetRect(nLeft+(int)(0.3*m_nWidth),(int)(0.4*m_nWidth)+m_nYmargin,nLeft+(int)(0.6*m_nWidth),(int)(0.7*m_nWidth)+m_nYmargin);
m_memDC.Ellipse(rect);
CRgn rgn1;
rgn1.CreateEllipticRgn(rect.left,rect.top,rect.right,rect.bottom);
m_memDC.FillRgn(&rgn1,&br);
rect.OffsetRect(0,(int)(0.8*m_nWidth)+m_nYmargin);
m_memDC.Ellipse(rect);
CRgn rgn2;
rgn2.CreateEllipticRgn(rect.left,rect.top,rect.right,rect.bottom);
m_memDC.FillRgn(&rgn2,&br);
br.DeleteObject();
rgn1.DeleteObject();
rgn2.DeleteObject();
}
热心网友
时间：2022-07-08 03:29
不知道是单片机还是FPGA
int a[100][2] //int to bcd
byte b[10]={...,...,...,....};bcd to 数码，视共阴共阳而定
int ge，shi；
ge=0;
shi = 0;
//初始化a
for(int i = 0; i < 100； i++）// int to bcd
{
a[i][1]=shi;
a[i][0]=ge;
ge++
if(ge >= 9)
{
ge = 0;
shi++;
}
}
int j = 0；
while（时钟触发）
{
shi = a[j][1];
ge = a[j][0];
74（1）的信号线 = b[shi]; //十位译码
74（2）的信号线 = b[ge]; //个位译码
j++; //或者说时钟在这儿触发
if(j>99)
{
j=0；
}
}
