设n为大于1的自然数,求证:[1/(n+1)]+[1/(n+2)]+[1/(n+3)]...+1/2n...
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[1/(n+1)]+[1/(n+2)]+[1/(n+3)]...+1/2n > 1/2n+1/2n+1/2n+...+1/2n(这里有n个1/2n) = 1 / 2
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