已知函数f(x)=2sinwxcoswx+2√3sin^wx-√3(w>0),当f(x1)-f(x2)=4时...
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f(x) = 2sinwxcoswx + 2√3(sinwx)^2 - √3
= sin2wx + √3(1-cos2wx) - √3
= sin2wx - √3cos2wx = 2sin(2wx-π/3)。
f(x1)-f(x2) = 4, 则 f(x1) = 2， f(x2) = -2，
2wx1-π/3 = π/2， 2wx2-π/3 = -π/2，
x1 = 5π/(12w), x2 = -π/(12w),
丨x1-x2丨= π/(2w) = π/2, w = 1
