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y‘=[(2x+1)^3]'*(3-4x)^5+(2x+1)^3*[(3-4x)^5]'
=3(2x+1)^2*(2x+1)'*(3-4x)^5+(2x+1)^3*5(3-4x)^4*(3-4x)'
=3(2x+1)^2*2*(3-4x)^5+(2x+1)^3*5(3-4x)^4*(-4)
=6(2x+1)^2*(3-4x)^5-20(2x+1)^3*(3-4x)^4
=-(2x+1)^2*(3-4x)^4(x-2)